《互换性与测量技术》复习题及答?- 百度文库

2026/1/13 21:30:30

3?25H7/p6 ?25+0.021 ?25+0.035 0+0.022

0

4?25P7/h6 ?25-0.014 -0.035 ?25-0.013

10ĸߣĸͣ

-0.015 0

1?70+0.105 +0.075 2?250-0.044 3?10-0.022 ⣺1Td=Oes-eiO

Td1=Oes1-ei1O=O+0.105-(+0.075)O=0.030mm

ãĹȼΪIT7 2Td=Oes-eiO

Td2=Oes2-ei2O=O(-0.105)-(-0.044)O=0.029mm

ãĹȼΪIT6 3Td=Oes-eiO

Td3=Oes3-ei3O=O0-(-0.022)O=0.022mm

ãĹȼΪIT8

ɴ˹֮ڶᾫߣᾫ͡

11.±ոӦеݣո Smax ߴ ES EI TD es ei Td min 1 2 3 20 40 80 ⣺ ߴ ES EI 0 TD es ei Td Smax min -0.009 0 0.025 0 +0.060 0.013 +0.041 +0.010 Smin max Sav av +0.024 Tf 0.058 -0.076 -0.055 Smin max Sav Sav av Tf ϶ ӯ 1 2 3 20 +0.021 0.021 -0.007 -0.020 0.013 +0.041 +0.007 +0.024 0.034 0.077 +0.060 0.017 -0.034 0 -0.076 -0.055 0.042 0.058 40 +0.026 +0.001 0.025 80 -0.009 -0.048 0.039 -0.019 0.019 +0.010 -0.048 12. һϵĿ׺Ϊ?30N8/h7,¼ּ㲢:

0

N8=( -0.003 -0.036 ), h7=( -0.021 )

(1)׵Ļƫ ES=-0.003,Ļƫ es=0 (2)׵ĹΪ0.033mm,ṫΪ0.021mm (3)ϵĻ׼ǻ;ǹϡ

(4)Ϲ0.054mm


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