Ñо¿ÎïÖʵÄʵÑé·½·¨µ¥Ôª²âÊÔÌâ
Ò»¡¢ Ñ¡ÔñÌ⣺£¨±¾ÌâÖÐÿÌâÖ»ÓÐÒ»¸ö·ûºÏÌâÒåµÄ´ð°¸£©
1¡¢½«»ìÔÚË®ÖÐµÄÆûÓÍ·ÖÀë³öÀ´×îºÃ²ÉÓà £¨ £© A¡¢ÝÍÈ¡ B¡¢·ÖÒº C¡¢ÕôÁó D¡¢¹ýÂË
2¡¢ÓÃÀ¨ºÅÖÐ×¢Ã÷µÄ·½·¨·ÖÀëÏÂÁи÷×é»ìºÏÎÆäÖв»ÕýÈ·µÄÊÇ £¨ £© A¡¢µªÆøºÍÑõÆø£¨Òº»¯ÕôÁó£© B¡¢Ê³ÑÎÖеÄɳÀù£¨Èܽâ¹ýÂË£©
C¡¢ÇâÑõ»¯Ìú½ºÌåºÍË®£¨¹ýÂË£© D¡¢»¨ÉúÓͺÍË®£¨·ÖÒº£©
3¡¢´Ó²Ýľ»ÒÖÐÌáÈ¡K2CO3£¬ÐèÒªÒÔϲ½Ö裺¢ÙÕô·¢ÈܼÁ£¬¢Ú¼ÓË®Èܽ⣬¢ÛÏ´µÓ²»ÈÜÎ
¢Ü¹ýÂË£¬¢Ý¸ÉÔï¹ÌÌå¡£ÕýÈ·µÄ²Ù×÷˳ÐòΪ£º £¨ £© A¡¢¢Ù¢Ú¢Û¢Ü¢Ý B¡¢¢Ú¢Ù¢Û¢Ü¢Ý C¡¢¢Ú¢Ü¢Û¢Ù¢Ý D¡¢¢Û¢Ù¢Ú¢Ü¢Ý 4¡¢Òª½«äåË®ÖеÄäåÌáÈ¡³öÀ´£¬ÐèÒªÓõ½µÄÒ»×éÒÇÆ÷ÊÇ £¨ £© A¡¢ÆÕͨ©¶·¡¢²£Á§°ô¡¢ÉÕ± B¡¢³¤¾±Â©¶·¡¢²£Á§°ô¡¢ÉÕ±
C¡¢´óÊԹܡ¢ÊԹܼС¢ÈÝÁ¿Æ¿ D¡¢·ÖҺ©¶·¡¢ÉÕ±¡¢Ìú¼Ų̈
5¡¢²»ÁíÓÃÈκÎÊÔ¼Á¾ÍÄܽ«ÏÂÁÐÎåÖÖÈÜÒº£º¢ÙCuCl2¡¢¢ÚNa2SO4¡¢¢ÛKCl¡¢¢ÜK2CO3¡¢¢ÝBaCl2
¼ø±ð³öÀ´£¬ÆäÕýÈ·µÄ¼ø±ð˳ÐòÊÇ £¨ £© A¡¢¢Ù¢Ú¢Ü¢Û¢Ý B¡¢¢Ü¢Ý¢Û¢Ú¢Ù C¡¢¢Ù¢Ü¢Ý¢Ú¢Û D¡¢¢Ù¢Ú¢Ü¢Ý¢Û
6¡¢Ìá´¿º¬ÓÐÉÙÁ¿Ba£¨NO£©3µÄKNO3£¬¿ÉʹÓõķ½·¨Îª £¨ £©
A¡¢¼ÓÈë¹ýÁ¿Na2CO3ÈÜÒº£¬¹ýÂË£¬³ýÈ¥³Áµí£¬ÈÜÒºÖв¹¼ÓÊÊÁ¿ÏõË᣻ B¡¢¼ÓÈë¹ýÁ¿K2SO4ÈÜÒº£¬¹ýÂË£¬³ýÈ¥³Áµí£¬ÈÜÒºÖв¹¼ÓÊÊÁ¿ÏõË᣻ C¡¢¼ÓÈë¹ýÁ¿Na2SO4ÈÜÒº£¬¹ýÂË£¬³ýÈ¥³Áµí£¬ÈÜÒºÖв¹¼ÓÊÊÁ¿ÏõË᣻ D¡¢¼ÓÈë¹ýÁ¿K2CO3ÈÜÒº£¬¹ýÂË£¬³ýÈ¥³Áµí£¬ÈÜÒºÖв¹¼ÓÊÊÁ¿ÏõË᣻
+
7¡¢¼ìÑéKÀë×ӵö²Ù×÷ÖУ¬ÕýÈ·µÄÊÇ £¨ £© A¡¢Ö±½ÓÓò¬Ë¿ÕºÈ¡ÊÔÑù B¡¢²¬Ë¿½Ó´¥µ½µÆÐ¾ÉÏׯÉÕ C¡¢Í¸¹ýÀ¶É«îܲ£Á§¿´»ðÑæÑÕÉ« D¡¢²¬Ë¿ÒªÔÚʳÑÎÈÜÒºÖÐÏ´µÓ
8¡¢Í¨¹ýÑæÉ«·´Ó¦¼ì²âµ½Li+µÄ´æÔÚ£¬Ôò»ðÑæÑÕÉ«ÊÇ £¨ £© A¡¢×©ºìÉ« B¡¢ÑóºìÉ« C¡¢»ÆÂÌÉ« D¡¢×ϺìÉ«
9¡¢¼ìÑéNH4+µÄ²Ù×÷ºÍÏÖÏóµÄÃèÊöÖУ¬ÕýÈ·µÄÊÇ £¨ £© A¡¢¸ÉÔïµÄʯÈïÊÔÖ½±äºì B¡¢ÊªÈóµÄʯÈïÊÔÖ½±äÀ¶ G¡¢ÎÅÈÜÒºµÄÆøÎ¶ D¡¢³¢ÈÜÒºµÄζµÀ 10¡¢ÏÂÊöʵÑéÏÖÏóÄÜÈ·¶¨ÊÔÑùÖÐÒ»¶¨ÓÐCl-µÄÊÇ £¨ £© A¡¢µÎ¼ÓAgNO3ÈÜÒºÓа×É«³Áµí
B¡¢µÎ¼ÓÏõËáËữµÄBa£¨NO3£©2Óа×É«³Áµí C¡¢µÎ¼ÓÏõËáËữµÄAgNO3ÈÜÒºÓа×É«³Áµí D¡¢µÎ¼ÓÁòËáËữµÄAgNO3ÈÜÒºÓа×É«³Áµí
11¡¢¼ìÑéÊÔÑùÖÐÓÐÎÞSO42-µÄ²Ù×÷¼°½áÂÛÕýÈ·µÄÊÇ £¨ £© A¡¢ÏȼÓHClÎÞÃ÷ÏÔÏÖÏó£¬ÔÙ¼ÓBaCl2Óа×É«³Áµí£¬Ò»¶¨ÓÐSO42¡ª B¡¢¼ÓHClËữµÄBaCl2Óа×É«³Áµí£¬Ò»¶¨ÓÐSO42¡ª
2¡ª
C¡¢µÎ¼ÓÏõËáËữµÄAgNO3ÈÜҺûÓа×É«³Áµí£¬Ò»¶¨Ã»ÓÐSO4 D¡¢µÎ¼ÓBaCl2Óа×É«³Áµí£¬Ò»¶¨ÓÐSO42¡ª
12¡¢¹ØÓÚÅäÖÆNaClÈÜÒºµÄÐðÊö²»ÕýÈ·µÄÊÇ £¨ £© A¡¢ÍÐÅÌÌìÆ½³ÆÈ¡58.50¿ËʳÑΣ¬¼ÓË®ÅäÖÆ³É1ÉýÈÜÒº£¬NaClÈÜҺŨ¶ÈΪ1mol/L£» B¡¢×ªÒÆÊ±£¬ÒªÓò£Á§°ôÒýÁ÷£»
C¡¢ÈܽâʳÑεÄÉձҪϴµÓ2¡«3´Î²¢½«Ï´µÓÒº×ªÒÆµ½ÈÝÁ¿Æ¿ÖУ»
1
D¡¢½Á°è¿É¼ÓËÙÈܽ⡣
13¡¢ÎªÁËÅäÖÆ100ml¡¢1mol/LNaOHÈÜÒº£¬ÒÔϵÄÐðÊöÕýÈ·µÄÊÇ £¨ £©
A¡¢4¿Ë¹ÌÌåÈܽâºóÁ¢¼´Óò£Á§°ôÒýÁ÷µ½ÈÝÁ¿Æ¿ÖУ»
B¡¢ÓÃÁ¿Í²È¡Ë®¼Óµ½ÈÝÁ¿Æ¿ÖУ¬Ö±µ½°¼ÒºÃæÇ¡ºÃÓë¿Ì¶ÈÏßÏàÇУ» C¡¢³ÆÁ¿¹ÌÌåʱҪÓÃÂËÖ½µæÔÚÍÐÅÌÉÏ£»
D¡¢ÓýºÍ·µÎ¹Ü¶¨ÈÝʱ£¬Èç¹ûÒºÃæ³¬¹ý¿Ì¶ÈÏߣ¬Ðû²¼ÊµÑéʧ°Ü£¬Ö»ÄÜÖØ×ö¡£¡®
¡ª3
14¡¢ÓÃ98£¥µÄŨÁòËᣨÃܶÈ1.84g¡¤cm£©ÅäÖÆ1mol/LµÄÏ¡ÁòËá100mL£¬ÒÔϵÄÐðÊö´íÎóµÄÊÇ £¨ £©
A¡¢ÓÃ100mLÁ¿Í²È¡5.4mLŨÁòËᣬϡÊÍÀäÖÁÊÒκó×ªÒÆÖÁ100mLÈÝÁ¿Æ¿ÖУ»
B¡¢Ï¡ÊÍʱ£¬½«Å¨ÁòËáÑØÉÕ±ÄÚ±Ú»º»ºµ¹ÈëÊ¢ÓÐ30mLË®µÄÉÕ±ÖУ» C¡¢½Ó½ü¿Ì¶ÈÏßʱ£¬Ó¦ÓýºÍ·µÎ¹Ü¶¨ÈÝ£» D¡¢ÉÕ±¡¢²£Á§°ôҪϴµÓ2¡«3´Î¡£ 15¡¢ÏÂÊöʵÑé²Ù×÷»òÏÖÏóÕýÈ·µÄÊÇ £¨ £©
A¡¢ÓóÎÇåʯ»ÒË®³ýÈ¥SO2ÆøÌåÖлìÓÐÉÙÁ¿µÄCO2£»
B¡¢ÈÝÁ¿Æ¿ÉϱêÓйæ¸ñºÍ²»Äܵ¹ÖõķûºÅ£» C¡¢ÕôÁóʱ³£ÔÚÉÕÆ¿ÖмÓÈëÉÙÐíËé´ÉƬ£»
D¡¢ÕôÁóʱÀäÈ´Ë®µÄÁ÷ÏòÓëÈÈÆøÁ÷µÄÁ÷ÏòÒ»Ö¡£ ¶þ¡¢Ñ¡ÔñÌ⣺£¨±¾Ìâ¿ÉÄÜÓв»Ö¹Ò»¸ö·ûºÏÌâÒåµÄ´ð°¸£©
16¡¢ÝÍÈ¡ÊÇ·ÖÀëÒºÌå»ìºÏÎïµÄÓÐЧÊֶΡ£½«äåË®ÖеÄäåÌáÈ¡³öÀ´£¬¿É¼ÓÈë £¨ £©
A¡¢¾Æ¾« B¡¢ÏõËáÒø C¡¢ËÄÂÈ»¯Ì¼ D¡¢ÂÈ·Â
17¡¢ÂȼҵÔÚ»¯¹¤Éú²úÖÐÕ¼ÓÐÊ®·ÖÖØÒªµÄµØÎ»£¬µç½âǰ¶Ô±¥ºÍʳÑÎË®ÏÈÒª½øÐо«ÖÆ£¬ÒÔ³ýÈ¥ÆäÖеÄÄàɳ¡¢Ca2+¡¢Mg2+¡¢Fe3+¡¢SO42¡ª¡£Æä²Ù×÷ÓУº¢Ù¼ÓÊÊÁ¿µÄÑÎËᣬ¢Ú¹ýÁ¿µÄBaCl2ÈÜÒº£¬¢Û¹ýÁ¿µÄNa2CO2ÈÜÒº£¬¢Ü¹ýÁ¿µÄNaOHÈÜÒº£¬¢Ý¹ýÂË¡£ ºÏÀíµÄ²Ù×÷²½ÖèÊÇ £¨ £©
A¡¢¢Ù¢Ú¢Û¢Ü¢Ý B¡¢¢Ú¢Û¢Ü¢Ù¢Ý C¡¢¢Ü¢Ú¢Û¢Ù¢Ý D¡¢¢Û¢Ü¢Ú¢Ù¢Ý 18¡¢ÓÉÓÚ¹¤Òµ»¯µÄ¼Ó¿ìºÍÉç»á»·±£ÀíÄîµÄµ±¡£¬ÔÚ¹¤Òµ·¢´ïµÄ³¤Èý½ÇºÍÖéÈý½ÇµØÇø£¬Ë®ÖʵĶñ»¯ÒÑÒýÆðÏ൱ÑÏÖØµÄºó¹û£¬ÓÃÕôÁóµÄ·½·¨¿ÉÒÔ»ñµÃ´¿¾»µÄÒûÓÃË®¡£ÊµÑéÊÒ
Óô˷¨ÖƱ¸´¿¾»Ë®µÄʵÑéÖУ¬²»ÐèÒªµÄÒÇÆ÷ÊÇ £¨ £©
A¡¢·ÖҺ©¶· B¡¢ÕôÁóÉÕÆ¿ C¡¢ÀäÄý¹Ü D¡¢ÊÔ¹Ü 19¡¢ÒÔÏÂÎïÖʵļìÑé²Ù×÷ÕýÈ·µÄÊÇ £¨ £©
A¡¢ÎÞÉ«ÆøÌå²»ÄÜʹºìɫʯÈïÊÔÖ½±äÀ¶£¬Ôò¸ÃÆøÌåÒ»¶¨²»ÊÇNH3£»
B¡¢ÔÚÊÔÑùÖÐÏȼÓÈëHNO3£¬ÔÙ¼ÓÈëAgNO3£¬Èç¹û²úÉú°×É«³Áµí£¬ÔòÒ»¶¨ÓÐCl-´æÔÚ£» C¡¢²¬Ë¿ÕºÈ¡ÊÔÑùׯÉÕ£¬»ðÑæ³Ê»ÆÉ«£¬ÔòÒ»¶¨Ö»ÓÐNa+´æÔÚ£»
D¡¢ÔÚÊÔÑùÖÐÏȼÓÈëHClÎÞÃ÷ÏÔÏÖÏó£¬ÔٵμÓBaCl2£¬ÈôÉú³É°×É«³Áµí£¬ÊÔÑùÖÐÓÐSO42-¡£ 20¡¢ÒÔϲÙ×÷²»»áÒýÆðÎó²îµÄÊÇ £¨ £©
A¡¢ÔÚ×ªÒÆÒºÌåǰÈÝÁ¿Æ¿ÖÐÓÐÉÙÁ¿ÕôÁóË®£»
B¡¢¶¨ÈÝÒ¡ÔȺó£¬ÒºÃæÒѵÍÓÚÈÝÁ¿Æ¿¿Ì¶ÈÏߣ¬´Ëʱ²»ÔÙ¼ÓË®£»
2
C¡¢×ªÒÆÊ±ÓÐÉÙÐíÒºÌåÑØÈÝÁ¿Æ¿Íâ±ÚÁ÷µ½ÊµÑé×ÀÉÏ£» D¡¢¶¨ÈÝʱ¸©ÊÓÒºÃæ¡£ Èý¡¢Ìî¿ÕÌ⣺
21¡¢Ð¡Íõͬѧ׼±¸ÓÃÁòËá;§ÌåÅäÖÆ480ml¡¢1mol/LµÄÈÜÒº¡£ ¢Å¡¢Ð¡Íõͬѧͨ¹ý¼ÆË㣬¾ö¶¨³ÆÈ¡______¿Ë¾§Ì壻
¢Æ¡¢ÔÚ½øÐгÆÁ¿²Ù×÷ʱ£¬Ð¡ÍõͬѧµÄµÚÒ»²½²Ù×÷ÊÇÔÚÌìÆ½µÄÍÐÅÌÉϸ÷·ÅÒ»ÕŵÈÖØµÄֽƬ£¬ËûµÄ²½ÖèÕýÈ·Óë·ñ_____£¨Ìî¡°ÕýÈ·¡±»ò¡°·ñ¡±£©£¬Èç²»ÕýÈ·£¬ÄãÈÏΪµÚÒ»²½ÊÇ__________¡£
¢Ç¡¢²£Á§°ôÔÚ¸ÃʵÑéÖÐÓÐÖØÒªµÄÓÃ;£¬·Ö±ðÊÇ_____ºÍ _______ ¡£
¢È¡¢Ð¡ÍõͬѧѡÓõÄÈÝÁ¿Æ¿ÈÝ»ýµÄ¹æ¸ñÊÇ_____ml£¬Ê¹ÓøÃÒÇÆ÷µÄµÚÒ»²½²Ù×÷ÊÇ______£¬¾ßÌå²Ù ×÷·½·¨ÊÇ__________________________________________________________________¡£ ¢É¡¢Èç¹û¸ÄÓÃÎÞË®ÁòËáÍ£¬Ð¡ÍõͬѧӦ¸Ã³ÆÈ¡_______¿Ë¡£
¢Ê¡¢ÅäÖÆºÃµÄÈÜÒº³Ê____É«¡£Ð¡Íõͬѧ»¹Ïëͨ¹ýʵÑéÀ´Ö¤ÊµÈÜÖʵijɷ֣¬ÇëΪËûÉè¼ÆÒ»Ì×·½°¸£ºCu2+___________________________________________________________________
2+
SO4__________________________________________________________________¡£
22¡¢·ÖÀëºÍÌá´¿ÏÂÁлìºÏÎ½«ºÏÀíµÄ·½·¨ÌîÈëÓұߵĿոñÄÚ£º »ìºÏÎï ·½·¨ ¢Å¡¢ÌáÈ¡²Ýľ»ÒÖеÄK2CO3¾§Ì壻 ¢Æ¡¢º£Ë®ÖÐÌáÈ¡ÒûÓÃË®£» ¢Ç¡¢µâË®ÖÐÌáÈ¡µâ£» ¢È¡¢´Ó̼ËáÄÆºÍʳÑεĻìºÏÎïÖлñÈ¡´¿ ¼î£» ¢É¡¢´ÓKNO3ÈÜÒºÖзÖÀëAgCl¿ÅÁ££» ¢Ê¡¢³ýȥˮÖеÄNa+¡¢Cl-£» ¢Ë¡¢³ýÈ¥Éúʯ»ÒÖлìÓÐÉÙÁ¿µÄ̼Ëá¸Æ ¢Ì¡¢ÌáȡɳÀùÖеĵ⠢͡¢³ýÈ¥CO2»ìÓÐÉÙÁ¿µÄHClÆøÌå ¢Î¡¢³ýÈ¥O2ÖÐÉÙÁ¿µÄCO2 ËÄ¡¢ÊµÑéÌ⣺ 23¡¢ÎªÈ·¶¨Ò»Æ¿NaOHÈÜÒºµÄŨ¶È£¬¿É²ÉÈ¡ÓÃÒÑ֪Ũ¶ÈµÄÑÎËá½øÐеζ¨µÄ·½·¨¡£¸ù¾Ý´Ë·½·¨µÄÏà¹Ø²Ù×÷£¬»Ø´ðÏÂÁÐÎÊÌ⣺
¢Å²Ù×÷ÖÐÐèÒªÓõ½µÄ²£Á§ÒÇÆ÷ÓÐ_______________________________£»
¢ÆÈ·¶¨·´Ó¦µÄÖÕµãÒªÓÃ_______ÊÔÒº£¬ÖÕµãµÄÑÕÉ«±ä»¯ÊÇ´Ó___ É«µ½____É«£¬ÇÒ____ʱ¼äÄÚ²»±ä»¯£»
¢Ç²Ù×÷ÖÐÑÛ¾¦Ó¦Ê¼ÖÕ×¢ÊÓ__________£» ¢ÈÈç¹ûNaOHµÄÌå»ýΪV£¨b£©£¬HClµÄŨ¶ÈΪc£¨a£©Ìå»ýV£¨a£©£¬Ôò²â¶¨µÄNaOHŨ¶ÈµÄ¼ÆËãʽΪ£ºc£¨NaOH£©=_____________________________£»
¢ÉÔÚµÎÈëNaOHµÄ¹ý³ÌÖУ¬²»É÷È÷³öÒ»µÎµ½×¶ÐÍÆ¿Í⣬Õâ»áµ¼ÖÂc£¨NaOH£©___£¨Æ«´ó¡¢Æ«Ð¡»ò²»±ä£©
24¡¢Ò»Ñ§ÉúÉè¼ÆÁËÈçÏÂʵÑé·½·¨·ÖÀëNaClºÍCaCl2Á½ÖÖ¹ÌÌåµÄ»ìºÏÎï¡£
3
Ìî¿ÕºÍ»Ø´ðÏÂÁÐÎÊÌ⣺
(1)BÎïÖÊÊÇ_____________(д»¯Ñ§Ê½)¡£
(2)½«´ËʵÑé·½·¨·ÖÀëµÃµ½µÄNaCl£¬¾·ÖÎöº¬ÓÐÔÓÖÊ£¬ÊÇÒòΪÉÏÊö·½·¨ÖÐijһ
²½Éè¼Æ
´íÎó£¬Çëд³ö´íÎóµÄÕâÒ»²½ÕýÈ·µÄÉè¼Æ·½°¸¡£
´ð£º____________________________________________________¡£
(3)ÈôÒª²â¶¨»ìºÏÎïNaClºÍCaCl2µÄÖÊÁ¿±È£¬¿Éͨ¹ý³ÆÁ¿BÎïÖʺÍÁíÒ»ÎïÖʵÄÖÊÁ¿À´È·¶¨£¬ÕâÖÖÎïÖÊÊÇ_____________¡£ Îå¡¢¼ÆËãÌ⣺ 25¡¢¼ÓÈÈ1.218g¾§ÌåRCl2.xH2O£¬Ê¹Ö®Ê§È¥È«²¿½á¾§Ë®µÃµ½0.570gRCl2£¬°ÑÕâЩRCl2ÈܽâÓÚË®Åä³É200mlÈÜÒº£¬È¡³ö100mlÈÜÒºÕýºÃÓë40ml 0.15mol/lAgNO3ÈÜÒºÍêÈ«·´Ó¦¡£Ôò
£¨1£© RÊÇÊ²Ã´ÔªËØ£¿ £¨2£© xµÄÊýÖµÊǶàÉÙ£¿
26¡¢ ij¹â±ʯ(KCl.MgCl2.6H2O)ÑùÆ·Öк¬Óв»ÓëÇâÑõ»¯ÄÆÈÜÒº¡¢ÑÎËáÈÜÒº·´Ó¦µÄÔÓÖÊ¡£Îª²â¶¨ÑùÆ·ÖÐKCl.MgCl26H20µÄÖÊÁ¿·ÖÊý£¬½øÐÐÁËÈçϱíËùʾµÄʵÑé¡£ÇëÍê³ÉÏÂÁÐÎÊÌ⣺
(1)Ìî³ä±íÖеÄÄÚÈÝ. ÐòºÅ ʵÑé²Ù×÷ ¢Ù ³ÆÈ¡agÑùÆ·,·ÅÈë×¶ÐÎÆ¿ÖмÓÊÊÁ¿Ë®ÈÜ½â ¢Ú ¢Û ¹ýÂ˲¢Ï´µÓ2-3´Î,ÊÕ¼¯ÂËÒº¼°Ï´ÒºÓÚÁíÒ»×¶ÐÎÆ¿ ¢Ü ÓÃcmol/lÑÎËáµÎ¶¨¹ýÁ¿µÄÇâÑõ»¯ÄÆÖÁÖÕµã,ÏûºÄÑÎËáV2ml (2)ÔÚ²½Öè3ÖÐ,Ö¤Ã÷³ÁµíÒѾϴµÓ¸É¾»µÄ²Ù×÷ÊÇ£º________________________________
________________________________________________________________________¡£
(3)ÑùÆ·ÖÐKCl.MgCl2.6H2OµÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿
4

