printf(\ return 0; }
解答: 1. int n; n=1; n++ continue;
2. #include\ n++ i++ break;
3. int n; n=1 n++ continue;
4. i<10 i++ num++ sum+=a
5. i=0; num=0; sum+=a; i++;
6. i=1 i++ (x%i==0) x=x/i;
7. i<=9 i++ j=1 j<=i
8. s=0 n<=20 n++ b=t;
9. s=0 n<=20 n++ s+=t;
10. b=1 n=1 n<=20 a=a+b
四.改错题 解答:
