何曼君第三版高分子物理答案
6、 x(2)的分子结构上具有非线性光学发色团,以及体系必须就是非中心反演对称。
00??EA??0.500??EA??EA??0.50EA8、解:??????????? ??0?00????0.111.89??CA??CA??0.11EA?1.89CA??CA? 得EA?0.50EA0?0.50?4.39(kcal?mol?1)1/2?2.195(kcal?mol?1)1/2 CA?0.11EA0?1.89CA0
?0.11?4.39(kcal?mol?1)1/2?1.89?1.14(kcal?mol?1)1/2 ?2.71(kcal?mol?1)1/2
0001?1.89?0.11??EB??EB??2EB?0.12CB??EB? ??? ??????????0?0???0.5??CB??CB??0.945?00.53CB??CB? EB?2EB0?0.12CB0
?2?0.68(kcal?mol?1)1/2?0.12?0.96(kcal?mol?1)1/2?1.19(kcal?mol?1)1/2 CB?0.53CB0?0.53?0.96(kcal?mol?1)1/2?0.51(kcal?mol?1)1/2 黏合焓的计算
(1)旧定义的敏感度计算黏合焓
?H??(EA0EB0?CA0CB0) ??(4.39?0.68?1.14?0.96)kcal?mol?1
??3.96kcal?mol?1 (2)新定义的敏感度计算黏合焓
?H??(EAEB?CACB)
??(2.195?1.19?2.71?0.51)kcal?mol?1 ??2.71kcal?mol?1 黏合功的计算
WAB??fnAB?H??6?10?6mol?m?2?(?2.71kcal?mol?1)?1.626?10kal?m?5?2
