凸輪壓力角： 1.滾子式從動件
??VI2,4?b??sdsdt?ds?d?dt?d??dsdtdsd??d?dt?dsd????v??b??v???b?v................................1.().. ?c?b???(s?d)tan??b?(s?d)tan???
?v?(s?d)tan???.....................(2.)...?d?RP??.........................3.)..(?122???tanv??s?R2P??2..................4.().
2.平面式從動件
壓力角 = 00，但存在Overturning Moment(翻轉力矩)的問題，要使翻轉力矩小，則d 的值要儘量小,因而影響到設計凸輪的大小
凸輪輪廓曲率半徑： 1. 滾子式從動件
?min??Rf.......................................................................(5)
?pitch??(RP2?s)?v222?32(RP?s)?2v?a(RP?s)dsd?22................................(6) wherev?dsd?............a?...................................................(7)
2. 平面式從動件
RA?x?i(Rb?s)RA?ce?cei(???)?i?i(???)?i??x?i(Rb?s).........................................................(8)real:ccos(???)?x............................................................................(9)imaginary:csin(???)???Rb?s.................................................................(10)
The center of curvature C is atationary on the cam that the magnitudes of c andρ, and angleα do not change for small changes in cam angleθ. (These values are not constant but at stationary values. Their first derivative with respect to θ are zero, but their higher derivatives are not zero)
Differentiating eq.(8) with respect to θ, yields:
icei(???)?dxd??idsd?..................................................................(11)real:?csin(???)?imaginary:dsd??v.................................................................(13) dxd?.....................................................................(12)ccos(???)??x?v.?dxd??dvd??a............................................................................(14)???Rb?s?a...........................................................................(15)
